(1)How many atoms of Sodium are present in 3 moles of Sodium and what is the
mass of it ?
Given data :
No of
moles of sodium = 3 mol
No of
sodium atoms = ?
Mass
of sodium = ?
Solution :
No of
sodium atoms = No of moles * NA
No of
sodium atoms = 3 * 6.02 * 1023
= 18.06 *
1023 atoms
Mass
of sodium = ?
Mass
of sodium = No of moles * Molar mass
Mass of sodium =?
Mass of sodium = No of moles * Molar mass
= 3*23
= 69 grams
(2) How many atoms are
in 1 amu and 1 g of hydrogen (H)?
Given Data :
Mass of Hydrogen = 1 amu
Mass of Hydrogen = 1 g
No. of Hydrogen atoms in both =?
Solution:
1 amu = 1.66* 10-24 g
Number of hydrogen atoms =Mass of hydrogen atoms/Molar mass *
NA
= 1.66*10-24/1 * 6.02*1023
= 0.999 atoms
= 9.99*10-1
= 1 atom
No. of hydrogen atoms in 1 gram=Mass of hydrogen/Molar mass*NA
No. of atoms of Hydrogen in 1 g = 1/1 *6.02*1023
= 6.02*1023 atoms
(3) How many atoms are
present in 16 g of O and 8 g of S?
Given Data :
Mass of O = 16 gram
Mass of S = 8 gram
No of atoms of both?
Solution :
No. of O atoms = Mass of O / Molar mass of O * NA
No. of O atoms = 16/ 16 * 6.02*1023
= 6.02*1023 atoms
No. of Sulphur atoms = Mass of S / Molar mass of S * NA
No. of S atoms = 8/ 32 * 6.02 *1023
= 1.5 * 1023 atoms
(4) Is the mass of 1
mole of O and 1 mole of S same?
1 atom of carbon means there is only 1 carbon atom. While 1
gram atom of carbon means the atomic mass of carbon expressed in grams which is
12g.
(5) If 16 g
of oxygen contains 1 mole of oxygen atoms calculate the mass of one atom of
oxygen in grams.
1 mole of O atoms = 16 grams
Also, 1 mole of O atoms = 6.02*1023 atoms
of O
6.02*1023 atoms of O has mass = 16 grams
1 atom of O has mass = 16 / 6.02*1023 * 1
= 2.65*10-23 grams
(7) How many times is 1 mole of oxygen atom heavier than 1 mole of
hydrogen atom?
1 mole of oxygen atom = 16 grams
1 mole of hydrogen atom = 1 gram
The ratio between these two will be
1:16
It means that 1 mole of oxygen atom
is 16 times heavier than 1 mole of hydrogen atom.

Mass of N2 = 10 grams Mass of CO = 10
grams
Molar mass of N2 = 28 g
mol-1 Molar
mass of CO = 28 g mol-1
No. of N2 molecules =? No. of CO molecules
= ?
No. of molecules of N2 No. molecules of CO
= Mass of N2/Molar mass*6.02*1023 = Mass of CO/ Molar mass *NA
= 10/28*6.02*1023
= 10/ 28
*6.02*1023
= 2.15*1023 molecules = 2.15*1023 molecules
10 g nitrogen gas contain the same number of molecules as 10
g of carbon monoxide because both have
the same molar mass i.e. 28 g mol-1
Informative for us
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